Dynamic HTML: The Definitive Reference
by Danny Goodman


The following changes were made in the 6/00 reprint:


{407}  MEDIA entry of <STYLE> tag;
Changed Default from "screen" to "all"


{411}  BACKGROUND entry;

Changed "NN n/a" back to "NN 4".  
Added the following to the description paragraph:

 For NN 4, you may have to nest your main table (with a transparent 
 background image) inside another table that bears the desired 
 background graphic.


{412}  BORDERCOLOR entry;

Changed "NN 4" and "HTML 4" to "NN n/a" and "HTML n/a".



[561]  write(), writeln() entry;

Under "Parameters", removed the second sentence and replaced it with:

 For a SCRIPT tag, use document.write("<" + "SCRIPT>"). For the
 end script hiding statement, use document.write("//--" + ">").

 
{679}  add() entry;

Deleted the last sentence of the description  and replaced it with:

 Using the add() method with a parameter that matches an existing 
 option's index value replaces the old item with the new one. You 
 cannot insert an item among existing items without rebuilding the 
 entire options array.  



{831}  scrollBy() entry;

Behavior of deltaX and deltaY is the reverse of what was described.

3rd and 4th sentences now read:

 Positive values for deltaX scroll the document to the left (so
 the user sees content to the right in the document); negative
 values scroll the document to the right.  Positive values for
 deltaY scroll the document upward (so the user sees content lower
 in the document); negative values scroll the document downward.


{865}  
Changed the CSS filter grayscale() to gray()

Also, in the "chroma()" line, put "color" in
CW in the second sentence ("The color parameter...").

And, in the "glow()" line, put "color" and "strength" in the
second sentence in CW ("The color parameter...and strength sets...").

And, in the "shadow()" line, put "color" in CW in the second
sentence ("The color parameter...").



{958}  Last sentence on page;
Did read:
         After an AND operation on these two values, the binary result
         is 0010; the decimal equivalent is 3.
Now reads:
         After an AND operation on these two values, the binary result
         is 0010; the decimal equivalent is 2.