December 2016
Intermediate to advanced
440 pages
9h 44m
Japanese
Content preview from アルゴリズムクイックリファレンス 第2版
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9.5
線分走査法
■
303
合、決定要因は、
線分走査法
の実行中に
LineState
によって保持される線分の平均
個数となる。それが小さければ（平面上のランダムな線について期待されるように）、
線分走査法
に軍配が上がる。
表9-4 ビュフォンの針問題に対するアルゴリズムの時間比較（ミリ秒）
n 線分走査法 力任せ 交差の平均個数 πの推定値 誤差
16 1.77 0.18 0.84 3.809524 9.072611
32 0.58 0.1 2.11 3.033175 4.536306
64 0.45 0.23 3.93 3.256997 2.268153
128 0.66 0.59 8.37 3.058542 1.134076
256 1.03 1.58 16.2 3.1644 0.567038
512 1.86 5.05 32.61 3.146896 0.283519
1,024 3.31 18.11 65.32 3.149316 0.14176
2,048 7 67.74 131.54 3.149316 0.07088
4,096 15.19 262.21 266.16 3.142912 0.03544
8,192 34.86 1028.83 544.81 3.12821 0.01772
第
2
の問題として、線分間に
O(n
2
)
の交点がある集合
S
を考える。
線分走査法
は、
LineState
で多くの交点について情報を保持するオーバーヘッドのために、性能が
著しく低下する。表 9-5は、力任せ法が
線分走査法 ...
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O’Reilly covers everything we've got, with content to help us build a world-class technology community, upgrade the capabilities and competencies of our teams, and improve overall team performance as well as their engagement.Julian F.
I wanted to learn C and C++, but it didn't click for me until I picked up an O'Reilly book. When I went on the O’Reilly platform, I was astonished to find all the books there, plus live events and sandboxes so you could play around with the technology.Addison B.
I’ve been on the O’Reilly platform for more than eight years. I use a couple of learning platforms, but I'm on O'Reilly more than anybody else. When you're there, you start learning. I'm never disappointed.Amir M.
I'm always learning. So when I got on to O'Reilly, I was like a kid in a candy store. There are playlists. There are answers. There's on-demand training. It's worth its weight in gold, in terms of what it allows me to do.