integral of i{P) over the entire receiving plane. In terms of dimensionless
variables we have
00
EE = KP)dv^ dVyl i{P)dv^
dVy.
(10.1.10)
-00
For a square aperture of side 2a we take a square area of side 2x at the PSF. To
find EE for the principal maximum we have x = Xi, v^ =
VyQ
= n. Substituting
for i(P) firom Eq. (10.1.6) and evaluating Eq. (10.1.10) at these limits, we find
EE = 0.815 for the principal maximum. Within a square enclosing the FWHM we
get EE = 0.52.
The final item of interest for a rectangular aperture is the case where a <^b,
hence a narrow slit in the y direction. In the limitin ...
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