
7-32 Calculus – Differentiation and Integration
Example 7.25 Trace the curve y x x x= − +
5 4 3
4 4 .
Solution: Given equation of the curve is y x x x x x x x x= − + = − + = −
5 4 3 3 2 3 2
4 4 4 4 2( ) ( ) .
1. If y = 0, then x = 0 or 2 and if x = 0, then y = 0.
Thus, x = 0 and 2 are x-intercepts and y = 0 is the y-intercept.
2. y' x x x x x x x= − + − = − −2 2 3 2 2 5 6
3