Problem 2

Step 1. The problem statement tells us to use /23.

Step 2. The subnets would be 10.0.0.0, 10.0.2.0, 10.0.4.0, 10.0.6.0, 10.0.8.0, and so on, counting by 2 in the third octet.

Step 4. Three of the first four new possible subnets (10.0.0.0/23, 10.0.2.0/23, and 10.0.6.0/23) all overlap with existing subnets.

Step 5. 10.0.4.0/23 is the numerically lowest new subnet number that does not overlap with the existing subnets.

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