Applying the Concepts

$C(x)=0.5x+\text{}2000$
$\overline{C}(x)=0.5+\text{}{\displaystyle \frac{2000}{x}}$
$\overline{C}(100)\text{}=20.5,$ $\overline{C}(500)=4.5,\text{}\overline{C}(1000)=\mathrm{2.5.}$ These show the average cost of producing 100, 500, and 1000 trinkets, respectively.
Horizontal asymptote: $y=0.5.$ It means the average cost (the fixed daily cost of producing each trinket) if the number of trinkets produced approaches $\infty $.


About 9 min
About 12 min
About 76 min
397 min

$\infty $;
Not applicable; the domain is $x<100$.
No

$3.02 billion
90.89%

16,000
The population will stabilize at 4000.

$f(x)=(10x+200,\text{}\mathrm{000\; ...}$
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