The process of taking projections on different hyperplanes is continued
until we get f
(M
\ which is obtained by taking the projection on the last
equation in (139). One now iterates by projecting f
(M)
on the first hyper plane
again. For example, for the two-dimensional case shown in Fig. 32 one
reprojects /
(2)
on the first hyperplane (in this case a line) to get f
{3)
. This
process continues until all the Μ hyperplanes have again been cycled through
resulting in f
(2M
\ The second iteration is started by projecting f
(2M)
onto
the first hyperplane again, and so on. Tanabe [56] has shown that if a
unique solution f
s
to the syste ...
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