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Electrical Applications 2 by David W. Tyler

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18 Transmission and distribution of electrical energy
238
V -
33.2 A (33.2-50) (33.2-150) (33.2-175)
33.2 A 16.8 A
116.8 A
f50A f100A T25A
245 V
141.8A
Figure 1.28
The minijnum terminal voltage is at the
50 A
load, since
currents flow towards this load from both ends
(Figure
1.28).
Load voltage = 238 - 33.2 x 0.05
= 236.34
V
(Answer (a))
The same result is achieved by working from the other end of
the feeder, subtracting the volt drops from 245 V.
(b) Losses = PR watts. Considering each section in turn:
Losses = 33.2
2
x 0.05 = 55.1 W
16.8
2
x 0.025 = 7.06