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Electrical Applications 2 by David W. Tyler

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Illumination 111
Figure 7.5
THE INVERSE SQUARE In Figure 7.5, the source of illumination has a luminous intensity of
LAW /candela. The level of illumination at surface A
x
is due to / lumens
on 1 square metre since the solid angle is 1 steradian.
E
=
I\ux
The light rays are all meant to be at right angles to the surface being
illuminated. If the surface A
x
is removed so that all the light rays
which illuminated it now travel two metres to illuminate surface A
2
,
the luminous flux has spread over four square metres. There are
now /lumens on 4 square metres.
E =