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as a whole to a voltage of this particular frequency, by completely
removing from it both L and C. This, leaving only/?, would result in
the flow of a current equal to E/R.
Let us assume a voltage not unlikely in radio broadcast reception,
and see what happens when Ε = 5 mV. The current at 796 kHz is
then 5/10 = 0.5 mA, and this current flows, not through R only, but
through L and C as well. Each of these has a reactance of 1000 Ω at
this frequency; the potential difference across each of them is
therefore 0.5 x 1000 =500 mV, which is just one hundred times the
voltage Ε of the generator to which the flow of current is due.
That a simpl ...