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Microwave Engineering
book

Microwave Engineering

by Ahmad Shahid Khan
May 2014
Intermediate to advanced content levelIntermediate to advanced
800 pages
24h 50m
English
CRC Press
Content preview from Microwave Engineering
82 Microwave Engineering
Solution
Given Z
R
= 200 Ω Z
0
= 50 Ω L = 0.4 μH/m
R = 0.1 Ω/m C = 40 pF/m G = 10
5
/m
Γ = (Z
R
Z
0
)/(Z
R
+ Z
0
) = (200 – 50)/(200 + 50) = 150/250 = 0.6
S = 1 +|Γ|/1 |Γ| = (1 + 0.6)/(1 – 0.6) = 1.6/0.4 = 4
ω
= 2
π
f = 2
π
× 50 × 10
6
= 3.1415927 × 10
8
rad/s
Q =
ω
L/R = 3.1415927 × 10
8
× 0.4 × 10
6
/0.1 = 3.1415927 × 400 = 1256.637
υ
= 1/LC = 1/(0.4 × 10
6
× 40 × 10
12
)
= 1/16 × 10
18
= 1/4 × 10
9
= 0.25 × 10
9
m/s
Q can also be obtained by using the relation Q =
β
/2
α
β
=
ω
/
υ
= 3.1415927 × 10
8
/0.25 × 10
9
= 0.31415927/0.25 = 1.256637 rad/m
α
0.0005 nepers/m
from Equation 2.75b and the relation
α
R/2Z
0
for smal
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Publisher Resources

ISBN: 9781466591417