Finally the combined phasor diagram can be drawn (Diagram 53).
The value of the capacitor current required to raise the P.F. to 0.95
lagging must be /
c
, which is the same distance (ab). By measurement:
Ic
= 0.6 A
0.6
= 400
Ω
But
Xc
=
2TT/C
C =
2-wfXc
1
2ττ x 50 x 400
fyF
Note: By measurement, the supply current is 0.45 A.
Rating
of fluorescent circuits
Fluorescent tubes are rated in watts, but as we have seen, the circuit of
which the lamp is part, is inductive, and even after improvement, has a
lagging P.F.
Diagram 53
Inductance and capacitance in installation work 41
We know from Chapter
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