as

dx1θ(t2t1|x2x1|c)θ(tt|x1x|c)=θ(t2t|x2x|c)D2dx1

(3.70)

As illustrated in Fig. 3.8a, the expression (3.69) can be rewritten in the form

x3|K^2n|x=(ωe222c)2θ(tt|xx|c)Ddxn1Dn1dxn2D2dx1,

(3.71)

where the region Dk is defined by the intersection of the cones tκtκ1|xκxκ1|c>0 and tκ1t1c|xκ1x|>0 and represents a parallelogram. To calculate the integrals in Eq. (3.71), it is convenient to use the new variables ui=12(cti+xi) and wi=12(ctixi), in which the regions of integration are transforming into rectangles Di (Fig. 3.8b).

Image

Figure 3.8 An example of regions for integration in (3.71).

After ...

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