June 2017
Beginner to intermediate
576 pages
15h 22m
English
Try this query on your own in a new script to determine which members had multiple purchases. There should be 89 of them. In SQL query parlance, the multiple purchases clause is indicated in the query by count(*) > 1:
dups <- sqldf("select member.memberid,count(*) from member left outer join purchases_filtered on member.memberid=purchases_filtered.memberid2 group by member.memberid having count(*) > 1")