
276 Probability Methods for Cost Uncertainty Analysis
The density function of Cost
Sys
conditioned on a system schedule of 35.65
months is normal, with mean 33,954.18 ($K) and variance 10,342,359.87 ($K)
2
To nd a such that P(Cost
Sys
≤ a
.
PrgmSched = 35.65 ) = 0.95, let
P(Cost
Sys
≤ a
a−33,954.18
where φ =
√
PrgmSched = 35.65 ) = P(Z ≤ φ)
10,342,359.87
. From Table A.1, P(Z ≤ φ) = 0.95 if
a − 33, 954.18
φ =
√
= 1.645
10, 342, 359.87
This implies that a = 39, 244.4. Thus, the cost of the digital information system
that has only a 5% chance of being exceeded, when conditioned on a schedule
having the same chance of being exceeded, ...