
136 Risk Analysis in Finance and Insurance
where C is a constant.
Since
X
T
= x exp
(1 − α)r + αμ −
α
2
σ
2
2
T + ασ W
t
%
,
then
E
X
T
= x exp
(1 − α)r + αμ
T
,
and we can prove the following result.
Theorem 4.2 If
min
α
CaR(x, α, T )
<C<xexp{rT},
then the optimization problem (4.38) has a unique solution α = εσ
−1
,where
ε =
μ −r
σ
+
z
λ
√
T
+
/
μ − r
σ
+
z
λ
√
T
2
− 2
ln
1 − C exp{−rT }/x
T
,
and
max E
X
T
= x exp
r + ε
μ −r
σ
T
.
Proof The assumption min
α
CaR(x, α, T )
<C<xexp{rT} implies that
the constraint CaR(x, α, T ) ≤ C is not redundant.
Since E
X
T
is an increasing function of α, we just need to find the max-
imum of α under the constraint CaR(x, α, T ) ≤ C.From
CaR(x, α, T )=