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Separation Process Engineering: Includes Mass Transfer Analysis, Fourth Edition by Phillip C. Wankat

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Answers to Selected Problems

Chapter 2

2.D1. a. y = 0.77, x = 0.48

b. V = 600.0 and L = 900.0

c. V/F = 0.25, y = 0.58

d. F = 37.5 kmol/h

e. D = 1.705 ft. Use 2.0 ft. L ranges from 6.0 to 10.0 ft.

f. V/F = 0.17

g. x = 0.756, V = 16.18 mol/h, L = 33.82 mol/h

2.D2. Hint: Work backward (start with stage 2).

a. (V/F)1 = 0.148

b. x1 = 0.51, y1 = 0.78, x2 = 0.25, y2 = 0.62

2.D8. V/F = 0.076, xmethane = 0.0077, xpropane = 0.0809

2.D9. Tdrum ∼ 88.2°C, xE = 0.146, yE = 0.617, V = 326.9

2.D15. zethane = 0.4677, znC4 = 0.2957

2.D18. Tdrum ∼ 65.6°C, V/F ∼ 0.57

2.D19. Tdrum ∼ 57.0°C, V/F = 0.293

2.F2. x3 = 0.22, y3 = 0.461

2.F3. Tdrum ∼ 57.3°C, V/F = 0.513

Chapter 3

3.D2. L/D = 2.77

3.D3. = 1532.4 kg/h

3.D5. a. B = 76.4 kg/min, D = 13.6 kg/min, Qc = –13,357 ...

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