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Shipboard Electrical Power Systems
book

Shipboard Electrical Power Systems

by Mukund R. Patel
December 2011
Intermediate to advanced content levelIntermediate to advanced
370 pages
12h 24m
English
CRC Press
Content preview from Shipboard Electrical Power Systems
334 Appendix A: Symmetrical Components
These two indications lead us to the sequence network shown in Figure A.3. For this
circuit, therefore, the total driving voltage divided by the total impedance gives the
current. The total driving voltage is the sum of three sequence voltages (that is, V
˜
1
+
V
˜
2
+ V
˜
o
), and the total impedance is Z
˜
1
+ Z
˜
2 + 20
+ (3 Z
˜
f
+ 3 Z
˜
g
+ 3 Z
˜
n
).
I
˜
1
= I
˜
2
= I
˜
o
= (V
˜
1
+ V
˜
2 +
V
˜
o
) ÷ (Z
˜
1
+ Z
˜
2
+ Z
˜
o
+ 3 Z
˜
f
+ 3 Z
˜
g
+ 3 Z
˜
n
) (A.10)
⅓ I
a
V
1
Z
1
Positive
sequence
network
V
2
Z
2
Negative
sequence
network
V
0
Z
0
Zero
sequence
network
V
a
3 Z
f
3 Z
n
3 Z
g
FIGURE A.3 Sequence networks connected in series for L-G fault (depen ...
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Publisher Resources

ISBN: 9781439828175