The Monty Hall problem might be the most contentious question in the history of probability. The scenario is simple, but the correct answer is so counterintuitive that many people just can’t accept it, and many smart people have embarrassed themselves not just by getting it wrong but by arguing the wrong side, aggressively, in public.
Monty Hall was the original host of the game show Let’s Make a Deal. The Monty Hall problem is based on one of the regular games on the show. If you are on the show, here’s what happens:
Monty shows you three closed doors and tells you that there is a prize behind each door: one prize is a car, the other two are less valuable prizes like peanut butter and fake finger nails. The prizes are arranged at random.
The object of the game is to guess which door has the car. If you guess right, you get to keep the car.
You pick a door, which we will call Door A. We’ll call the other doors B and C.
Before opening the door you chose, Monty increases the suspense by opening either Door B or C, whichever does not have the car. (If the car is actually behind Door A, Monty can safely open B or C, so he chooses one at random.)
Then Monty offers you the option to stick with your original choice or switch to the one remaining unopened door.
The question is, should you “stick” or “switch” or does it make no difference?
Most people have the strong intuition that it makes no difference. There are two doors left, they reason, so the chance that ...
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