salvage, life, period[,
The initial cost of the asset.
The value of the asset at the end of
Length of life of the asset.
Period for which the depreciation is to be calculated.
The rate at which the asset balance declines. If omitted, 2 (double-declining method) is assumed. However, the documentation doesn’t mention what other values are supported or what they mean.
Double representing the depreciation of an asset
Returns a Double representing the depreciation of an asset for a
specific time period. This is done using the double-declining balance
method or another method that you specify using the
The double-declining balance calculates depreciation at a differential rate, which varies inversely with the age of the asset. Depreciation is highest at the beginning of an asset’s life and declines over time.
must be specified in the same time units. In other words, both must
be expressed in units of months, or both must be years.
All arguments must be positive numbers.
Dim dblInitialCost As Double = 2000 Dim dblSalvageValue As Double = 50 Dim dblUsefulLife As Double = 12 Dim dblTotDepreciation As Double = 0 Dim dblPeriod, dblThisPeriodDepr As Double For dblPeriod = 1 To 12 dblThisPeriodDepr = DDB(dblInitialCost, ...