=m=0K10πdϕ wm(ϕ)1Kk=1KUm(x_n_ϕκ)Um(cos(ϕkϕ))(4.127)
=1Kk=1Km=0K1Um(x_n_ϕκ)0πdϕ wm(ϕ)Um(cos(ϕkϕ))=m+12cm(ϕk).(4.128)

In this way, we have been able to discretize the angle, but it seems that we still need the full – i.e., continuous – information (f)(ϕk , s) for each angle ϕk. On the other hand, we also know that the RT equals a polynomial of at most order K − 1 in s, up to a prefactor of 1s2see equation (4.116). Therefore, the right hand side of

cm(ϕk)=2π11ds(Rf)(ϕk,s)Um(s),(4,129)

is an integral over a polynomial of at most order 2(K − 1), multiplied ...

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