Chapter 6
1: | Find the value of quack after each line.int quack = 2; quack += 5; quack *= 10; quack -= 6; quack /= 8; quack %= 3; |
A1: | 2, 7, 70, 64, 8, 2 |
2: | Given that value is an int, what output would the following loop produce?for ( value = 36; value > 0; value /= 2) printf("%3d", value); What problems would there be if value were double instead of int? |
A2: | It would produce the following output:
36 18 9 4 2 1 If value were double, the test would remain true even when value became less than 1. The loop would continue until floating-point underflow yielded a value of 0. Also, the %3d specifier would be the wrong choice. |
3: | Represent each of the following test conditions:
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