C++ Primer Plus

Program Notes

In most contexts, C++ interprets the name of an array as the address of its first element. Thus, the following statement makes pw a pointer to type double and then initializes pw to wages, which is the address of the first element of the wages array:

double * pw = wages;

For wages, as with any array, we have the following equality:

wages = &wages[0] = address of first element of array

Just to show that this is no jive, the program explicitly uses the address operator in the expression &stacks[0] to initialize the ps pointer to the first element of the stacks array.

Next, the program inspects the values of pw and *pw. The first is an address, and the second is the value at that address. Because pw points to the first element, the ...