Problem 3

Step 1. The problem statement tells us to use /22.

Step 2. The subnets would be 10.0.0.0, 10.0.4.0, 10.0.8.0, 10.0.12.0, and so on, counting by 4 in the third octet.

Step 3. The first two new possible subnets (10.0.0.0/22 and 10.0.4.0/22) overlap with existing subnets.

Step 4. 10.0.8.0/22 is the numerically lowest new subnet number that does not overlap with the existing subnets.

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