Answers to Selected Problems
Chapter 1
-
- 432,000 Coulombs
- 11.66 V
- 88.18 AH
- 3.76 × 106 J, 1.045 kWh
-
- 28 AH
- 9 A
- 2.94 × 106 J, 0.817 kWh 8.9 A, 71.2 AH
-
- 10 AH
- 60 AH
- 10 A
- 2.133 × 106 J, 0.593 kWh
-
- a 100 Ω resistor
- 0.36 mC
- 1 mC
- 5 mJ
- 23 ms
-
- a 0.1 μF capacitor
- 1 μC
- 5 μJ
- 3.75 μJ
-
- a 0.6 H inductor
-
- –240 W
- 120 J , increases
- It is a resistor of 5 Ω and the current through it is (2 – e–1000t) A for t ≥ 0.
- (d) 0.85 A
-
- 9.97 A, 1.994 ...
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