September 2008
Beginner
834 pages
37h 13m
English
Solving for the particular integral of a differential equation for sinusoidal input has been rendered easy by the use of complex exponential function as shown in the previous sections. However, deriving the differential equation remains a tedious affair even now. Arriving at the proper elimination steps requires considerable ingenuity in the case of circuits containing many inductors and capacitors, but we can avoid all that. We proceed to see how.
The steady-state response of the second mesh current i2 in the circuit in Fig. 8.3-1 for a complex exponential input of Vmejωt was noted as
. We evaluate this for ω = 1 rad/s. ...
Read now
Unlock full access