## Answers to Selected Problems and Questions

Chapter 1 Introduction to Image Processing

1-4(1) 256 × 256 × (1 + 8 + 1)/9,600 = 68.3 s.

(2)1024 × 1024 [3(1 + 8 + 1)]/38,400 = 819.2 s.

1-8The minimum gray level is 0 (every position is 0), the maximum gray level is 12 (every position is 3), during which the gray levels can be continuous, so this template can represent a total of 13 gray levels. × 1024 ×

Chapter 2 Image Acquisition

2-3The camera coordinates are (–0.2, –0.4, 0). The image plane coordinates are (–0.2, –0.4).

$I=\frac{\Phi}{\Omega}=\frac{\Phi}{4\pi}$

The luminance at the distance r is

$B=\frac{1}{S}=\frac{1}{4\pi {r}^{2}}=\frac{\Phi}{{\left(4\pi r\right)}^{2}}$

Taking the values of r into the above formula, we get

$\begin{array}{l}{B}_{50}=\frac{\Phi}{}\end{array}$

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