461An Introduction to Two-Dimensional Compressible Flow
Now consider the boundary conditions at the surface as discussed in the derivation of
Equation 14.47. Let
y = f(x)
describe the shape of the actual body and let
η = F(ζ)
describe the shape of the body in the transformed plane.
The boundary condition in the actual ow is
=
Φ
p
s
y
u
df
dx
(14.60)
whereas in the transformed plane the boundary condition is
=
Φ
p
s
u
dF
d
ηζ
(14.61)
However,
=
=
ΦΦ Φ
p
s
p
s
p
s
y
y
yη
β
η
β
β
() ()
1
i.e.,
=
ΦΦ
p
s
p
s
yη
(14.62)
Equation 14.62 therefore shows that the lef-hand side of Equations 14.60 and 14.61 are
equal, so
df
dx
dF
d
=
ζ
(14.63)
This means that the shape of the body is the same in real and the transformed planes,
i.e., the function that relates y to x on the surface of the body in the real plane is identi-
cal to the function that relates η to ζ on the surface of the body in the transformed plane.
Since Φ
p
is determined by Equation 14.59, which is identical to the equation that applies
in incompressible ow, and since the shape of the body is the same in the real and trans-
formed planes, it follows that
Φ
p
is the same as the linearized velocity potential function
that would exist in incompressible ow over the body being considered. Hence, if
Φ
p
is
462 Introduction to Compressible Fluid Flow
determined from the solution for incompressible ow over the body, the actual linearized
velocity potential and x and y being given by
ΦΦ Φ
pp p
Mx
yM
== −=== // //βζηβ η
11
22
,,
Now, Equation 14.54 gives
C
udxud
p
pp
=−
=−
∞∞
22
ΦΦ()
/β
ζ
i.e.,
C
ud
p
p
=−
12
βζ
Φ
(14.64)
However, the variation of
Φ
p
with ζ is the same as in incompressible ow over the body
shape being considered, i.e., by virtue of Equation 14.54, Equation 14.64 gives
CC
C
M
pp
p
==
1
1
0
0
2
β
(14.65)
where C
p0
is the value of the pressure coefcient that would exist in incompressible ow
over the body being considered. This means that if the pressure coefcient distribution is
determined for incompressible irrotational ow, the pressure coefcient distribution is com-
pressible ow at Mach number M
can be found by applying a “compressibility correction
factor” equal to
11
2
/
M
. This only applies in subsonic ows, i.e., to ows in which M
< 1.
Consider the lift force on a body, i.e., the force normal to the upstream ow, resulting
from the variation in the pressure over the surface of the body. If L is the lift per unit span,
it will be seen from Figure 14.11 that
Lp
pd
s=−
()cosθ
the integral being carried out over the surface of the body.
Lift
p
θ
θ
u
p
ds
FIGURE 14.11
Calculation of lift from pressure distribution.
463An Introduction to Two-Dimensional Compressible Flow
This equation can be written as
C
L
uc
Cd
s
c
Lp
=
=
∞∞
1
2
2
ρ
θcos (14.66)
where C
L
is the lift coefcient and c is the wing chord. From Equation 14.65, it follows that
C
C
M
L
L
=
0
2
1
(14.67)
C
L0
being the lift coefcient that would exist in incompressible ow. Since
11
2
−<
M
, the
above equations indicate that compressibility increases the coefcient of lift.
Now for smaller angles of attack, α, this being dened in Figure 14.12, C
L
= aα in incom-
pressible ow. In compressible ow, then
Ca
M
L
=−
α/1
2
. This is shown in Figure 14.13.
Lift
Drag
Angle of
attack
u
α
FIGURE 14.12
Denition of airfoil angle of attack.
Compressible
flow
Angle of attack, α
i.e., incompressible
flow
a (= slope of line)
M
<< 1
Coefficient of lift, C
L
a/√M
2
–1
FIGURE 14.13
Effect of compressibility on lift coefcient variation.
464 Introduction to Compressible Fluid Flow
Linearized Supersonic Flow
In supersonic ow disturbances are, as discussed in Chapter 2, propagated along Mach
lines as indicated in Figure 14.14.
The ow upstream of the Mach line is undisturbed by the presence of the wave. It is to
be expected therefore that the perturbation velocity potential, Φ
p
, will, in supersonic ow,
be constant along a Mach line. Now, along a Mach line
y
x
M
=
1
1
2
i.e.,
xM y
=−
2
1
where it has again been noted that because sin α = 1/M
,
tan/α=
11
2
M
.
Hence, it is to be expected that
ϕ
p
= f(xλy) = f(η) (14.68)
where
λ=
M
2
1 (14.69)
and
η = xλy (14.70)
Small disturbance
Mach wave
y
x
M
α = sin
–1
(1/M
)
FIGURE 14.14
Mach wave.

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