Chapter 12
Solutions to the Exercises
EXERCISE 3.1.– We can represent an interpretation as a subset of Π, with the elements of this subset being the propositional symbols that are evaluated to T in the interpretation.
There are 2ℵo subsets of Π; hence, there is an uncountably infinite number of interpretations for PL.
A more detailed proof.
Every interpretation I can be represented by the graph of the function defining it:
There are infinitely many interpretations, take for example (l ):
Now if we assume that the set of all interpretations in PL is denumerable, then they can be enumerated (i ):
Consider the interpretation defined as follows:
This interpretation is different from every ...
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