Since { w[ n ],z[ n ] }n = 0N  1 are i.i.d. exponential random variables, their PDF are p(w[n]) = λ exp(−λw[n]) and p(z[n]) = λ exp(−λz[n]), respectively. The likelihood function of { x1[ n ],x2[ n ] }n = 0N  1 is then given by n = 0N  1p(w[ n ])p(z[ n ]). Substituting (10.32) and (10.33) into the likelihood function, we obtain the expression:

p({ x1[ n ],x2[ n ] }n = 0N  1|λ,θ1,θ0,d) = λ2Nexp{   λn = 0N  1[ (x1[ n ]  t2[ n ])θ1 + (x2[ n ]  t1[ n ])  2d ] }n = 0N  1I[ x1[ n ]θ1  θ0  d  t1[ n ]0 ]n = 0N  1I[   t2[ n ]θ1 + θ0  d + x2[ n ]0 ],

(10.34)

where we have used the transformations θ0β0/β1 and θ1 ≔ 1/β1, and I[·] is the indicator function. Notice that from the invariance property, the ML estimate ...

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