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253Conduction and Switching Losses

And by that time, the drain current would have reached only 5 A. The gate voltage would

at that moment be only at 5

V. However, no further change in Id is possible (even if we

increase Vgs further). Therefore, though the crossover interval has become half of what it

was, the rise time of the current is still equal to the fall time of the voltage (i.e., 5 s). This

is a characteristic only of resistive loads (since V  IR applies to them).

The rules of the game change considerably, when we have an inductive load. In fact the

calculation becomes simpler—ironically because the simplicity (and ...