April 2015
Beginner
400 pages
8h 45m
English
Content preview from Probability and Statistics
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Additional Solved Problems
Example 1
A 10-digit number is formed using the digit from 0 to 9, every digit being used only once. Find the probability that the number is divisible by 4.
Solution The 10 digits can be arranged in 10! ways. Of these 9! will begin with the digit 0. The total number of 10 digit numbers formed is 10! − 9! = 36,28,800 − 3,62,880 = 32,65,920.
A number will be divisible by 4 if the last two digit number is divisible by 4, i.e. if it 04, 08, 12, 16, 20, 24, 28, 32, 36, 40, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 92 or 96. Of 10 digit numbers ending with
04 are 8! = 40,320
12 are 8! − 7! = 35,280 (zero is part of 8 digit numbers)
20 are 8! = 40,320
24 are 8! − 7! = 35,280 (zero is part of 8 digit numbers)
32 are 8! − ...
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