Appendix 8. Answers to Exercises
Chapter 2
Chapter 5
1. Accumulated time T=50×100=5000 hr. Since the test was time truncated n=2(k+1).
Therefore,
(a)n=6, T=5000, α=0.4. From Appendix 2, χ2=6.21
(b)n=2, T=5000, α=0.4. From Appendix 2, χ2=1.83
2. If k=0 then n=2 and since confidence level=90%, α=0.1
Therefore ...
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