Let us take *x*1(*n*) = *a ^{n}u*(

The *z*-transform of *x*_{1}(*n*) = *a ^{n}u*(

The given function is

∴ *X*[*z*] = *Z*[*nx*_{1}(*n*)]

By differentiation property of *z*-transform, we can write

Therefore, the *z*-transform of *x*(*n*) = *n* *a ^{n}u*(

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