Chapter 12
Introduction to Nonlinear Regression
12.1 As θ2 decreases, the curve becomes steeper.
12.3 As θ3 increases, the curve becomes steeper.
12.5 a. As θ2 decreases, the curve becomes steeper.
b. As x → ∞, E(y) → 1.
c. When x = 0, E(y) = θ1 exp{−θ2}.
12.7 a. This is an intrinsically linear model.
b. The model is nonlinear.
c. The model is nonlinear.
d. This is an intrinsically linear model.
e. The model is nonlinear.
12.9 
= −.121x2 + 1.066e.4928x1. An approximate 95% confidence interval for θ3 is (−1.027, .785). Since this interval contains 0, we conclude there is no difference in the two days.
= −.121x2 + 1.066e.4928x1. An approximate 95% confidence interval for θ3 is (−1.027, .785). Since this interval contains 0, we conclude there is no difference in the two days.12.11 a.
b. = .3896 − (−.2194)e−.0992x. The starting values were obtained by plotting ...
= .3896 − (−.2194)e−.0992x. The starting values were obtained by plotting ...Get Solutions Manual to Accompany Introduction to Linear Regression Analysis, 5th Edition now with the O’Reilly learning platform.
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