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Statistical Techniques for Transportation Engineering by Naresh Davergave, Anil Shah, G Rao, Kumar Molugaram

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Probability that a washer is defective

=1Probabilitythatawasherisnotdefective=10.7698=0.2302

image

Therefore the percentage of defective washers=23.02.

Example 4.93: The mean of a normal distribution is 60 and 6% of the values are greater than 70. Find the SD of the distribution?

Solution: Let X denote the normal random variable

We have P(X>70)=6100=0.6image (given)

Therefore

P(xμσ>70μσ)=0.6

i.e.,

P(Z>7060σ)=0.6

or

P(Z>10σ)=0.6

Let Z1=10/

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