$\begin{array}{ll}{\mu}_{4}\hfill & ={\mu \prime}_{4}-4{\mu \prime}_{3}{\mu \prime}_{1}+6{\mu \prime}_{2}{({\mu \prime}_{1})}^{2}-3{({\mu \prime}_{1})}^{4}\hfill \\ =26\u20134(5.5)(1)+6(2.5)(1)+3{(1)}^{4}\hfill \\ =26\u201322+15\u20133=16\hfill \\ {\mu}_{1}\hfill & =0,{\mu}_{2}=1.5,{\mu}_{3}=0,{\mu}_{4}=16\hfill \end{array}$

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