Student Solutions Manual Applied Statistics and Probability for Engineers, Fifth Edition

CHAPTER 4

Section 4-2

4-1.      a)   

b)   

c)   

d)   

e)   

f)   

Then, x = – ln(0.10) = 2.3.

g)   

Then, x = –ln(0.9) = 0.1054

4-3.      a)   

b)   

c)   

d)   

e)   

Then, sin x = 0.9, and x = 1.1198 radians.

4-5.      a)   , because f_X (x) = 0 for x < 3

b)    because f_X (x) = 0 for x > 5

c)