CHAPTER 7
Section 7-2
7-1. The proportion of arrivals for chest pain is 8 among 103 total arrivals. The proportion = 8/103
7-3.
7-5.
7-7. Assuming a normal distribution,
7-9 σ2 =25
7-11. n =36
Using the central limit theorem: = P(0.7348 < Z < 3.6742) = P(Z < 3.6742) − P(Z < 0.7348) = 1 − 0.7688 = 0.2312
7-13.
a)
b)
7-15. Assume approximate normal distributions.
Section 7-3
7-17. a)
b) Estimate of mean of population = sample mean ...
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