Table of Integrals, Series, and Products, 8th Edition

1038 $\begin{array}{cc}{J}_{\nu }\left(ax\right),\hfill & \text{Re}\nu \text{>}-\text{1}\hfill \end{array}$	$\begin{array}{l}{a}^{-\nu }{\left(\sqrt{s^2+a^2}-s\right)}^{\nu }{\left(s^2+a^2\right)}^{-1/2},\hfill \\ \text{Re}s>\left|\text{Im}a\right|\hfill \end{array}$ET I 182(1)
104 $\begin{array}{cc}x{J}_{\nu }\left(ax\right),\hfill & \text{Re}\nu \text{>}-2\hfill \end{array}$	$\begin{array}{l}{a}^{\nu }\left[s+\nu {\left(s^2+a^2\right)}^{1/2}\right]{\left[s+{\left(s^2+a^2\right)}^{1/2}\right]}^{-\nu }\hfill \\ \times {\left(s^2+a^2\right)}^{-3/2},\hfill \\ \text{Re}s>\left|\text{Im}a\right|\hfill \end{array}$ET I 182(2)
105 $\frac{J_{\nu }\left(ax\right)}{x}$	$\begin{array}{l}{a}^{\nu }{\nu }^{-1}{\left[s+{\left(s^2+a^2\right)}^{1/2}\right]}^{-\nu },\hfill \\ \text{Re}\hfill \end{array}$