Using now the Aubin property of Fi around (a,bi) (with constant LFi > 0) with i2,k¯ one gets that for a neighborhood V of bi and for every n sufficiently large

bi+tn(βni+bni)Fi(a+tn(αni+an))VFi(a+tn(αn+an))+LFitnαniαnDY,

for all i2,k¯

In conclusion, for every i2,k¯, there exists ( fni) ⊂ Dy such that λni=βni+LFiαniαnfni0 and

bi+tn(bni+λni)Fi(a+tn(αn+an)).

Since i=1pbniw, using (8.25), it follows that all the sequences (an),( ani),( bnj) are bounded with ik+1,p¯, j1,p¯. Hence, for every n sufficiently large,

tn((αn,λn1,λn2,,λnk,αnk+1,λnk+1,,αnp,λnp)+(an,bn1,bn2,,bnk,ank+1,,anp,bnp))+(a,b1,b2,,bk,ak+1,bk+1,,ap,bp)[Gr(F1,F2,,Fk)×i=k+1pGrFi]W,

(8.26)

as the above sequence converges ...

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