January 2017
Intermediate to advanced
768 pages
27h 45m
English
In the case of a nonlinear initial value problem
the hypothesis in Theorem 1 that f satisfies a Lipschitz condition on a slab (x, t) (t in I, all x) is unrealistic and rarely satisfied. This is illustrated by the following simple example.
Consider the initial value problem
As we saw in Example 6, the equation does not satisfy a “strip Lipschitz condition.” When we solve (36) by separation of variables, we get
Because the denominator vanishes for Eq. (37) provides a solution of the initial value problem in (36) only for despite the fact that the differential equation “looks nice” on the entire real line—certainly the function ...
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