
Mixed States, Open Systems, and the Density Operator 97
• |ψ
1
i =
1
√
2
(|00i + |01i). This is a Bell state and is already in Schmidt
form. It is clearly entangled: it has 2 terms.
• |ψ
2
i =
1
2
(|00i + |01i + |10i + |11i) =
1
√
2
(|0i + |1i)
1
√
2
(|0i + |1i)) has
only one term: it is a product state.
• |ψ
3
i =
1
√
3
(|00i + |01i + |10i). This and more general states are more
tricky. We would need to find the SVD of the matrix of coefficients C
ij
for the state represented in the computational basis.
In our example, C =
1
√
3
"
1 1
1 0
#
, which turns out to be directly diago-
nalizable. So the SVD reduces to diagonalization.
Eigenvalues are λ
1,2
=
1
2
√
3
(1 ±
√
5) and normalized eigenvectors ...