Java 11 and 12 – New Features

The unescape() method

By default, the raw string literals don't interpret the escape sequences. However, what if you want them to do so? When used with a raw string, the unescape() method will match the sequence of the characters following \ with the sequence of Unicode escapes and escape sequences, as defined in the Java Language Specifications (JLS). If a match is found, the escape sequence will not be used as a regular combination of letters; it will be used as an escape sequence.

The following code doesn't interpret \n as a newline escape sequence:

System.out.print("eJava"); 
System.out.print("\\n");             
System.out.print("Guru"); 

The output of the preceding code is as follows:

eJava\nGuru 

However, the following code will interpret \n as ...