December 2019
Beginner to intermediate
330 pages
10h 7m
Chinese
Content preview from RxJava反应式编程
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操作符与转换
｜
83
//B
flatMap(innerObs -> just(innerObs)
.delay(rnd.nextInt(5), SECONDS))
在变种
A
中，Observable 会立即出现在外层流中，但是在一定延迟之后才会发布事件。
在变种
B
中，我们及时转移了整个 Observable 的事件，所以它出现在外层 Observable
中的时间要晚得多。现在，已经介绍了为何需要这么复杂的操作符。静态的 concat()
和 merge() 操作符都能操作由固定列表组成的 Observable，或者由 Observable 组成的
Observable
。而对
switchOnNext()
来说，后者会生效。
switchOnNext() 首先会订阅一个外层的 Observable<Observable<T>>，这个外层 Observable
会发布内层的 Observable<T>。第一个内层 Observable<T> 出现的时候，这个操作符就
会订阅它并开始往下游推送 T 类型的事件。下一个内层 Observable<T> 出现的话，会发
生什么呢？ switchOnNext() 将会取消对第一个 Observable<T> 的订阅，从而丢弃第一个
Observable<T>，然后切换至下一个 Observable<T>（这种做法也符合它的名称）。换句话
说，如果有一个用流组成的流时，switchOnNext() 只会往下游转发最后的内部流的事件，
即便旧的流依然在生成新的事件也会被丢弃。 ...
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