Advanced C++ Programming Cookbook

How it works...

In C++11, the standards committee added the ability to automatically deduce a template function's type information based on the arguments that were passed to the function.

Check out this example:

template<typename T>void foo(T t){    show_type(t);}

The preceding function creates a standard template function that executes a function called show_type() designed to output the type information that it is provided with.

Before C++11, we would use this function as follows:

int main(void){    int i = 42;    foo<int>(i);    foo<int>(42);}

The compiler already knows that the template should define the T type as an integer as that is what the function was provided for. C++11 removes this redundancy, allowing the following:

int main(void){ int i ...