April 2018
Intermediate to advanced
322 pages
6h 57m
English
Suppose we have a sorted array containing these 15 elements {3, 8, 11, 15, 16, 23, 28, 30, 32, 39, 42, 44, 47, 48, 50} and we need to find the position of 16. The first thing the binary search does is to find the middle element, then compares it with the searched value. Since we've got 15 elements on the list, the middle index is 7 (since the array is a zero-based index), and the value of the index is 30. Then, we compare 30 with our searched value, which is 16. Since the middle value is greater than the value we are looking for, the searched value must be to the left of the middle index. So, we can take the left subarray and have these elements: {3, 8, 11, 15, 16, 23, 28}. Again, we perform the binary search ...