Programming and Data Structures by Pearson

280 Programming and Data Structures

I

for (i=l,i<=5-l,i++)

for (j=l,i<=5-ij++)

if(strcmp(name[j-l],name[j])>0)

I

strcpy(temp,name[j-l]);

strcpy(name[j-l],name[j]);

strcpy(name[j],temp);

strcpy(temp,mobilelj-l]);

strcpy(mobile[j-l],mobile[j]);

} strcpy(mobile[j],temp);

printf ("L is t o f Customers in alphabetical Order.");

for (i=0,i<5;i++)

print)f("\n% -20s\t% -10s\n",name[i],m obile[i]);

OUTPUT:

Enter Names and Mobile Numbers.

K S MORE 458454

JMCHATE 658963

M M GORE 660585

L K jA IN 547855

j J JOSHI 354258

List of Customers in alphabetical Order.

CHATEJM 658963

GORE M M 660585

JAIN LK 547855

JOSHI JJ 354258

MOKE KS 458454

Explanation