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Programming and Data Structures by Pearson

Name: Programming and Data Structures by Pearson
Author: Ashok N. Kamthane
ISBN: 9781299446373

by Ashok N. Kamthane

May 2024

Intermediate to advanced

603 pages

21h 38m

English

Pearson India

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Cover
Preface
Contents (1/2)
Contents (2/2)
Course Syllabus
Chapter 1: Program Development Styles and Basics of C
1.1 Program Development MethodologiesMonolithic Programming
Procedural Programming
1.2 Programming Style
1.3 Stepwise Refinement and Modularity
1.4 Problem Solving Techniques
1.5 Algorithm

Classification of Algorithms
1.6 Flowcharts
1.7 Pseudocode
1.8 Sequence and Selection
1.9 Iteration and Recursion
Iteration
Recursion
1.10 Recursion Versus Iteration
1.11 Overview of Compilers and Interpreters
1.12 Structure of A C Program
1.13 Programming Rules
1.14 Executing the Program
SummaryExercises
Chapter 2: The C Declarations
2.1 Introduction2.2 The C Character Set
2.3 Delimiters
2.4 The C Keywords
2.5 Identifiers2.6 Constants
A. Numerical Constants
B. Character Constants2.7 Variables
2.8 Rules for Defining Variables
2.9 'C' Aggregate Data Types
Basic Data Type
Derived Data Type
2.10 Declaring Variables
2.11 Initializing Variables
2.12 Type Conversion
Summary
Exercises
Chapter 3: Operators and Expressions
3.1 Introduction
3.2 Priority of Operators and their Clubbing
3.3 Comma and Conditional Operator
Syntax
3.4 Arithmetic Operators
3.5 Relational Operators
3.6 Logical Operators
3.7 Bitwise Operators (1/2)
3.7 Bitwise Operators (2/2)
Summary
Exercises
Chapter 4: Input and Output in C
4.1 Introduction
4.2 Formatted Functions
Syntax (1/2)
Syntax (2/2)
4.3 Unformatted Functions
a) Character I/O
b) String I/O
Syntax
Syntax
4.4 Commonly Used Library Functions
SyntaxSyntaxSyntaxSyntaxSummary
Exercises
Chapter 5: Decision Statements
5.1 Introduction
5.2 The if Statement
5.3 The if . . . else Statement
5.4 Nested if - else Statement (1/2)
5.4 Nested if - else Statement (2/2)
5.5 The break Statement
5.6 The continue Statement
5.7 The goto Statement
5.8 The switch Statement (1/3)
5.8 The switch Statement (2/3)
5.8 The switch Statement (3/3)
5.9 Nested switch () Case
5.10 The switch () Case and Nested IFS
Summary
Exercises
Chapter 6: Loop Control Statements
6.1 Introduction
6.2 The for Loop (1/4)
6.2 The for Loop (2/4)
6.2 The for Loop (3/4)
6.2 The for Loop (4/4)
6.3 Nested for Loops (1/6)
6.3 Nested for Loops (2/6)
6.3 Nested for Loops (3/6)
6.3 Nested for Loops (4/6)
6.3 Nested for Loops (5/6)
6.3 Nested for Loops (6/6)
6.4 The while Loop (1/3)
6.4 The while Loop (2/3)
6.4 The while Loop (3/3)
6.5 The do-while (1/2)
6.5 The do-while (2/2)
6.6 The do-while Statement with while Loop
Summary
Exercises
Chapter 7: Arrays
7.1 Introduction
7.2 Array Initialization
7.3 Definition of Array7.4 Characteristic of Array
7.5 One-dimensional Array (1/3)
7.5 One-dimensional Array (2/3)
7.5 One-dimensional Array (3/3)
7.6 Predefined Streams
7.7 Two-dimensional Array (1/4)
7.7 Two-dimensional Array (2/4)
7.7 Two-dimensional Array (3/4)
7.7 Two-dimensional Array (4/4)
7.8 Three- or Multi-dimensional Arrays
7.9 The sscanf () and sprintf () Functions
Summary
Exercises
Chapter 8: Working with Strings & Standard Functions
8.1 Introduction8.2 Declaration and Initialization of String
The Output will be SANJAY
8.3 Display of Strings with Different Formats
Where, the text is 'PRABHAKAR'
8.4 String Standard Functions (1/5)
8.4 String Standard Functions (2/5)
8.4 String Standard Functions (3/5)
8.4 String Standard Functions (4/5)
8.4 String Standard Functions (5/5)
8.5 Applications of Strings (1/2)
8.5 Applications of Strings (2/2)
Summary
Exercises
Chapter 9: Pointers
9.1 Introduction9.2 Features of Pointers
9.3 Pointer Declaration (1/2)
9.3 Pointer Declaration (2/2)
9.4 Arithmetic Operations with Pointers
9.5 Pointers and Arrays (1/2)
9.5 Pointers and Arrays (2/2)
9.6 Pointers and Two-dimensional Arrays
9.7 Array of Pointers
9.8 Pointers to Pointers
9.9 Pointers and Strings (1/2)
9.9 Pointers and Strings (2/2)
9.10 Void Pointers
Summary
Exercises
Chapter 10: Functions
10.1 Introduction
10.2 Definition of a Function
Why use FunctionsHow a Function Works10.3 Declaration of a Function
10.4 The Return Statement
10.5 Types of Functions (1/2)
10.5 Types of Functions (2/2)
10.6 Call by Value and Reference
10.7 Function Returning More Values
10.8 Function as an Argument
10.9 Functions with Arrays and Pointers (1/2)
10.9 Functions with Arrays and Pointers (2/2)
10.10 Recursion
Summary
Exercises
Chapter 11: Preprocessor Directives
11.1 Introduction11.2 The #define Directive
11.3 Undefining a Macro
Syntax
11.4 Token Pasting and Stringizing Operators
11.5 The # include Directive
11.6 Conditional Compilation
Syntax
11.7 The #ifndef Directive
11.8 The #error Directive
11.9 The # line Directive
11.10 Inline Directive
11.11 The #pragma Saveregs11.12 The #pragma DirectiveSyntax
11.13 The Predefined Macros in Ansi and Turbo C
11.14 Standard I/O Predefined Streams in stdio.h
11.15 The Predefined Macros inctype. h
Summary
Exercises
Chapter 12: Structure and Union
12.1 Introduction12.2 Features of Structures
12.3 Declaration and Initialization of Structures
12.4 Structure within Structure
12.5 Array of Structures
12.6 Pointer to Structure
12.7 Structure and Functions
12.8 typedef
12.9 Bit Fields
12.10 Enumerated Data Type
12.11 Union
12.12 Calling Bios and Dos Services (1/2)
12.12 Calling Bios and Dos Services (2/2)
12.13 Union of Structures
Summary
Exercises
Chapter 13: Files
13.1 IntroductionA) Definition of File13.2 Streams and File Types
A) File Types
13.3 Steps for File Operations
Syntax for opening the file
A. Text Modes
Syntax
Syntax
Syntax
B Binary Modes
13.4 File I/O
Syntax
13.5 Structures Read and Write
13.6 Other File Function
13.7 Searching Errors in Reading/Writing Files (1/3)
13.7 Searching Errors in Reading/Writing Files (2/3)
13.7 Searching Errors in Reading/Writing Files (3/3)
13.8 Low Level Disk I/O
13.9 Command Line Arguments
13.10 Application of Command Line Arguments
3. Rename
13.11 Environment Variables
13.12 I/O Re direction
Summary
Exercises
Chapter 14: Linear Data Structure
14.1 Introduction to Data Structure
14.2 List
14.3 Implementation of a List
14.4 Traversal of a List
14.5 Searching and Retrieving an Element
14.6 Predecessor and Successor
14.7 Insertion
14.8 Deletion
14.9 Sorting
14.10 Merging Lists
14.11 Representation of a Stack
14.12 Stack-Related Terms
14.13 Operation on a Stack
14.14 Implementation of a Stack
14.15 Queues
14.16 Various Positions of Queue
14.17 Representation of Queue
14.18 Single Linked List
14.19 Linked List with and without Header
Linked List with Header
Linked List without Header
14.20 Insertion
Insertion of the Node at the Starting
Insertion of the Node at the End
Insertion of a Node at a Given Position
Counting Nodes
14.21 Deletion
14.22 Double Linked List
Insertion
Deletion
14.23 Applications
Polynomial OperationLinked Dictionary
Summary
Exercises
Chapter 15: Non-Linear Data Structure
15.1 Trees15.2 Binary Trees
15.3 Types of Binary Tree
15.4 Binary Tree Representation
15.5 Traversing Binary Trees (1/2)
15.5 Traversing Binary Trees (2/2)
15.6 Binary Search Tree
15.7 Insertion and Deletion Operations
15.8 Hashing Technology (1/3)
15.8 Hashing Technology (2/3)
15.8 Hashing Technology (3/3)
Summary
Exercises
Chapter 16: Searching and Sorting
16.1 Introduction
16.2 Searching
16.3 Linear (Sequential) Search
16.4 Binary Search
16.5 Sorting
16.6 Insertion Sort
16.7 Selection Sort
Time Complexity
Comparison with Other Methods
16.8 Bubble Sort
Time Complexity
16.9 Quick Sort
Time Complexity
Comparison with Other Methods16.10 Tree Sort
Time Complexity
SummaryExercises

Content preview from Programming and Data Structures by Pearson

582 Programming and Data Structures

Time Complexity

The efficiency of quick sort depends upon the selection of pivot. The pivot can bifurcate the list

into compartments. Sometimes, the compartments are having the same sizes or dissimilar sizes.

Assume a case in which pivot is at middle. Thus, the total elements towards lift of it and right are

equal.

We can express the size of list with the power of 2. The mathematical representation for the size

is n-2s. The value of s can be calculated as log2 n.

After the first pass is completed there will be two compartments having equal number of elements

that is, m/2 elements are on the left side as w

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by Ashok N. Kamthane

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