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Scala Cookbook
book

Scala Cookbook

by Alvin Alexander
August 2013
Intermediate to advanced
720 pages
16h 23m
English
O'Reilly Media, Inc.
Content preview from Scala Cookbook

15.4. Parsing JSON Data into an Array of Objects

Problem

You have a JSON string that represents an array of objects, and you need to deserialize it into objects you can use in your Scala application.

Solution

Use a combination of methods from the Lift-JSON library. The following example demonstrates how to deserialize the string jsonString into a series of EmailAccount objects, printing each object as it is deserialized:

import net.liftweb.json.DefaultFormats
import net.liftweb.json._

// a case class to match the JSON data
case class EmailAccount(
  accountName: String,
  url: String,
  username: String,
  password: String,
  minutesBetweenChecks: Int,
  usersOfInterest: List[String]
)

object ParseJsonArray extends App {

  implicit val formats = DefaultFormats

  // a JSON string that represents a list of EmailAccount instances
  val jsonString ="""
{
  "accounts": [
  { "emailAccount": {
    "accountName": "YMail",
    "username": "USERNAME",
    "password": "PASSWORD",
    "url": "imap.yahoo.com",
    "minutesBetweenChecks": 1,
    "usersOfInterest": ["barney", "betty", "wilma"]
  }},
  { "emailAccount": {
    "accountName": "Gmail",
    "username": "USER",
    "password": "PASS",
    "url": "imap.gmail.com",
    "minutesBetweenChecks": 1,
    "usersOfInterest": ["pebbles", "bam-bam"]
  }}
  ]
}
"""

  // json is a JValue instance
  val json = parse(jsonString)

  val elements = (json \\ "emailAccount").children
  for (acct <- elements) {
    val m = acct.extract[EmailAccount]
    println(s"Account: ${m.url}, ${m.username}, ${m.password}")
    println(" Users: " ...
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Publisher Resources

ISBN: 9781449340292Errata Page